(1/16)^2x+1=(4)^3x-1

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Solution for (1/16)^2x+1=(4)^3x-1 equation: 



(1/16)^2x+1=(4)^3x-1

We move all terms to the left:

(1/16)^2x+1-((4)^3x-1)=0



Domain of the equation: 16)^2x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/16)^2x-(4^3x-1)+1=0

We get rid of parentheses

(+1/16)^2x-4^3x+1+1=0

We multiply all the terms by the denominator


(+1-4^3x*16)^2x+1*16)^2x+1*16)^2x=0

Wy multiply elements

256x^2+(+1-4^3x*16)^2x=0

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